I'm confused because everyone else is saying that the bromobenzene is the limiting reagent. One method involves its conversion to the Grignard reagent, phenylmagnesium bromide. You should be putting your reagents in terms of mols; you can't compare grams of one substance to grams of another. The numbers you've provided would imply that magnesium is the limiting reagent as there are fewers moles magnesium compared to bromobenzene. This is apparently a thing now that people are writing exams from home. Press question mark to learn the rest of the keyboard shortcuts. Make benzyl alcohol from bromobenzene b. It is a reagent in organic synthesis. Photochlorination (4,092 words) exact match in snippet view article find links to article mono-substituted benzyl chloride. the 122.12 g/mol is the molar mass of benzoic acid. in the reaction with carbon dioxide to prepare benzoic acid. Get more help from Chegg. Chloroacetate + Cyclohexanone, + Chlorobenzene, + Bromobenzene, or + Benzyl Alcohol at (298.15, 303.15, and 308.15) K". Bromobenzene is used as a precursor in the manufacture of phencyclidine. Make pentane from butane c. Make tert-butyl alcohol from butane d. Make formaldehyde from methane. Benzyl alcohol can be synthesized from bromobenzene and simple organic/inorganic reagents. , Except where otherwise noted, data are given for materials in their, "IFA - Databases on hazardous substance (GESTIS): GESTIS database on hazardous substances", https://en.wikipedia.org/w/index.php?title=Bromobenzene&oldid=936809883, Pages using collapsible list with both background and text-align in titlestyle, Articles containing unverified chemical infoboxes, Creative Commons Attribution-ShareAlike License, This page was last edited on 21 January 2020, at 03:42. Press J to jump to the feed. Bromobenzene is prepared by the action of bromine on benzene in the presence of Lewis acid catalysts such as ferric bromide.. Bromobenzene is used to introduce a phenyl group into other compounds. Journal of Chemical & Engineering. Part 1 out of 2 Bromobenzene is an aryl halide, C6H5Br. Please do not post entire problem sets or questions that you haven't attempted to answer yourself.  Other methods involve palladium-catalyzed coupling reactions such as the Suzuki reaction. , For liver toxicity, the 3,4-epoxide are proposed intermediates. Bromobenzene and magnesium form benzoic acid in a 1:1 mol ratio. Draw the compounds to show how benzyl alcohol can be synthesized. Where is this 122.12 g/mol coming from? Synthesis and reactions. For Bromobenzene: 0.70mL bromobenzene * (1.495g/mL) *(1 mol / 157.01g) = 0.00667 mol bromobenzene For Magnesium: 0.15g Mg * (1 mol / 24.3 g) = 0.00617 mol Mg. One method involves its conversion to the Grignard reagent, phenylmagnesium bromide.This reagent can be used, e.g. The numbers you've provided would imply that magnesium is the limiting reagent as there are fewers moles magnesium compared to bromobenzene. I would check to make sure that your starting amounts are correct and after that I would ask to see someone else's calculations so you can see why you are getting a different result compared to them; worry less about what result they got and more about how they got it. in the reaction with carbon dioxide to prepare benzoic acid. Bromobenzene is used to introduce a phenyl group into other compounds. Animal tests indicate low toxicity. This reagent can be used, e.g.  Little is known about chronic effects. New comments cannot be posted and votes cannot be cast. I just checked the lab book again and the numbers are correct. Bromobenzene is prepared by the action of bromine on benzene in the presence of Lewis acid catalysts such as ferric bromide. Bromobenzene + Magnesium --> Phenylmagnesium Bromide, In the experiment I used 0.70mL bromobenzene and 0.15g Magnesium turnings, 0.70mL bromobenzene * 1.495 g/mL * (1 mol / 157.01g) * 122.12 g/mol = 0.814g benzoic acid, 0.15g magnesium * (1 mol / 24.3g) * 122.12 g/mol = 0.754 g benzoic acid, Does this make magnesium the limiting reagent? It is a colourless liquid although older samples can appear yellow. Post your questions about chemistry, whether they're school related or just out of general interest. If they got their answers erroneously, forget about it. Also please don't use this sub to cheat on your exams!!